Matematika

Pertanyaan

suku ke 4 dan suku ke 9 baris arimatika berturut adalah 110 dan 150. suku ke 30 ?

2 Jawaban

  • U4= a + 3b = 110
    U9= a + 8b = 150
    ------------------------- -
    -5b = -40
    b = 8
    a + 3b = 110
    a + 3(8) = 110
    a + 24 = 110
    a = 110-24
    a = 86

    U30 = a + (n-1)b
    = 86 + (30-1) 8
    = 86 + (29) 8
    = 86 + 232
    = 318
  • U4 = a + 3 b = 110
    U9 = a + 8 b = 150
    ______________ -
    -5b = -40
    b = -40 / -5
    b = 8
    a + 3 b = 110
    a + 3.8 = 110
    a = 110 - 24
    a = 86
    U30 = a + 29 b= 86 + 29.8
    = 86 + 232 = 318

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