Matematika

Pertanyaan

7√27+ 3√12 - √300 =
3 log 81 + 2 log 32 -5 log 125=

2 Jawaban

  • 7√27+3√12-√300
    =7.3√3+3.2√3-10√3
    =21√3+6√3-10√3
    =(21+6-10)√3
    =17√3

    3log81+2log32-5log125
    =4+5+3
    =12
  • 7√27+ 3√12 - √300
    =7√9√3 + 3√4√3 - √100√3
    =7.3√3 + 3.2√3 - 10√3
    =21√3 + 6√3 - 10√3
    =(21+6-10)√3
    =17√3

    ³log 81 + ²log 32 - ^5log 125
    =³log 3⁴ + ²log 2^5 - ^5log 5³
    =4 ³log 3 + 5 ²log 2 - 3 ^5log 5
    =4.1 + 5.1 - 3.1
    =4+5-3
    =6

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