Soal matematika. Tolong bantu ya. Thanks.

Misal x1 = (p + 2) dan x2 = (p - 3)
x^2 - 3x + 3m - 1 = 0
x1 + x2 = -b/a
(p + 2) + (p - 3) = -(-3)/1
2p - 1 = 3
2p = 4
p = 2
x1 = (p + 2) = 2 + 2 = 4
x2 = (p - 3) = 2 - 3 = -1
x1.x2 = c/a
4(-1) = (3m - 1)/1
-4 = 3m - 1
-3m = 3
m = -1

Jadi persamaan kuadrat yang akar-akarnya
(p + m) = (2 + (-1)) = 1 dan pm = 2(-1) = -2 adalah
x^2 - (1 + (-2))x + 1(-2) = 0
x^2 + x - 2 = 0