Berapakah molaritas larutan NaOH jika sebanyak 4 gram NaOH terlarut dalam 200ml (ArNa 23 O16 H 1)

M = m/Mr x 1000/v = 4/40 x 1000/200 = 0,1 x 5 = 0,5 M

Diketahui :
- massa = 4 gram
- Mr NaOH = (23 + 16 + 1) = 40
- v = 200ml
Ditanya : M?
Jawab :
M = massa/Mr x 1000/v
= 4/40 x 1000/200
= 0,1 x 5
= 0,5 M
Semoga membantu;))