Kimia

Pertanyaan

bantuin dong soal kimia
bantuin dong soal kimia

1 Jawaban

  • ▶ Langkah pertama cari jumlah mol masing2 larutan .
    Jumlah mol CH3COOH = M x V = 0,1 x 100 = 10 mmol
    Jumlah mol CH3COOHNa = M x V = 0,1 x 200 = 20 mmol

    ▶ langkah kedua mencari [H+]
    [H+] = ka x a/g
    = 10^-5 x 10/20
    = 5 x 10^-6

    ▶ langkah terakhir menghitung PH
    PH = - log [H+]
    = - log 5 x 10^-6
    = 6 - log 5

    Semoga membantu;))