Sebuah taman Berbentuk persegi panjang dg ukuran panjang (5x-2)cm,dan lebar (3x+1) meter. Jika keliling taman 62 meter, maka luas taman adalah?

keliling persegi panjang = 2x (panjang + lebar)
62 = 2x (5x-2+3x+1)
62 : 2 = 8x - 1
31 = 8x - 1
31 + 1 = 8x
32 = 8x
32 : 8 = x
4 = x

panjang = 5x - 2 = 5 x 4 - 2 = 18, lebar = 3x+1 = 3x4 + 1 = 13
luas = p x l = 18 x 13 = 234

62 = (5x-2)+(5x-2)+(3x+1)+(3x+1)
62 = 16x-2
64= 16x
x= 4
L= p*l
L= (5*4-2)*(3*4+1)
L=18*13
L=234