Diketahui persamaan linear x+2/2 - x-y/3 = 1, x+y/3 - y+1/2 = 2 Nilai x+y adalah

(x+2)/2 - (x-y)/3 = 1
3(x+2) - 2(x-y) = 6
x-2y = 0 ...(1)
...
(x+y)/3 - (y+1)/2 = 2
2(x+y) - 3(y+1) = 12
2x-y = 15 ...(2)

x-2y = 0 --- kalikan 2
2x-y = 15
------------- —
..-3y = -15
......y = 5
→ x -2(5) = 0 → x = 10

Maka, x+y = 10+5 = 15