nilai dari 3log2 x 2log3 -2log 1\16

itu duanya bisa alngsung dicoret jadi sisa 3log3 - 2 log1/16

3log3 = 1
2 log1/16 = -4

jadi 1 -(-4)
= 5

³ log 2.² log 3 - ² log 1/16
= ³ log 2. ² log 3 - ² log 16⁻¹
= ³ log 2. ² log 3 - ² log 2⁻⁴
= ³ log 3 - ² log ⁻⁴
= 1 -(-4)
= 1+4
= 5

good luck