Soal nomor 54 dan 56 Matmatika

54) f(x) = 1/x
f(g(x)) = (x - 3)/2x
1/g(x) = (x - 3)/2x
g(x) = 2x/(x - 3) ====> 2 dan -3 ditukar posisi dan berubah tanda
g^-1(x) = 3x/(x - 2)

56) f^-1(x) = (x - 1)/5 => f^-1(6) = (6 - 1)/5 = 5/5 = 1
g^-1(x) = (3 - x)/2

(f o g)^-1(6) = (g^-1 o f^-1)(6)
= g^-1(f^-1(6))
= g^-1(1)
= (3 - 1)/2 = 2/2 = 1