Fisika

Pertanyaan

mohon bantuannya yah !!!!
mohon bantuannya yah !!!!

1 Jawaban

  • a = F / (m₁ + m₂ + m₃)
       = 30 N / (10 kg + 5 kg + 15 kg) = 1 m/s²

    F - Fk₁₂ = m₁a
    Fk₁₂ = F - m₁a
            = 30 N - (10 kg)(1 m/s²) = 20 N

    Fk₂₁ - Fk₂₃ = m₂a
    Fk₂₃ = Fk₂₁ - m₂a
            = (20 N) - (5 kg)(1 m/s²) = 15 N
    atau
    Fk₃₂ = m₃a
            = (15 kg)(1 m/s²) = 15 N

    Fk₁₂ / Fk₃₂ = (20 N) / (15 N)
    Fk₁₂ : Fk₃₂ = 4 : 3