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69 DERAJAT F = ........ DERAJAT C
69 DERAJAT F =.......... DERAJAT R
69 DERAJAT F =............DERAJAT K
30 DERAJAT R =............DERAJAT C
30 DERAJAT R =........... .DERAJAT F
30 DERAJAT R =...........DERAJAT K
    CARANYA ..

1 Jawaban

  • t°F = 5/9 x ( t - 32 )°C
    69° F = 5/9 x (69 - 32) = 5/9 x 37 = 185/9 = 2,5°C
     t°F = 4/9 x ( t - 32 )°R  
    69°F = 4/9 x ( 69 -32 )°R = 4/9 x 37 = 148/9 = 16,44°R 
    t°F = 5/9 x ( t - 32 )°C
    69°F = 5/9 x (69 -32) = 5/9 x 37 = 185/9 = 2,5°C
             =  2,5 + 273 K = 275,5 K
    t°R = 5/4 x t°C
    30°R = 5/4 x 30°C = 150/4 = 37,5°C
    t°R = (9/4 x t) + 32°F
    30°R = (9/4 x 30) +32°F = 270/4 +32°F = 67,5 + 30°F = 97,5°F
    t°R = 5/4 x t°C
    30°R = 5/4 x 30°C = 150/4 = 37,5°C + 273 K =310,5 K
          

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