Bagaimana cara mencari f(×)= x3- 3x2 + 10 titik stasioner f'(×)= 0 f'(×) = 3x2 - 6x bagaimana cara bisa dapat f'(×) = 3x2 - 6x ...?

f(x) = x^3 - 3x^2 + 10
f'(x) = 3x^(3 - 1) - 3(2)x^(2 - 1) + 0
f'(x) = 3x^2 - 6x
Titik stasioner diperoleh jika f'(x) = 0
3x^2 - 6x = 0
3x(x - 2) = 0
3x = 0 => x = 0
(x - 2) = 0 => x = 2
Masukkan ke f(x) = x^3 - 3x^2 + 10
x = 0 => f(0) = 0^3 - 3(0)^2 + 10 = 10 => (0,10)
x = 2 => f(2) = 2^3 - 3(2)^2 + 10 = 8 - 12 + 10 = 6 => (2,6)
Titik stasioner nya : (0,10) => titik stasioner maksimum dan (2,6) => titik stasioner minimum