Fisika

Pertanyaan

suatu fungsi memiliki rumus f(x) = ax + b dengan nilai f(-2)= -1 dan f(1) = 11. nilai 5a + b =

sama caranya ya,hehe

1 Jawaban

  • f(x) = ax + b
    f(-2) = a (-2) + b = -1
    -2a + b = -1

    f(1) = a (1) + b = 11
    a + b = 11

    》-2a + b = -1
    a + b = 11
    ---------------------- -
    -3a = -12
    a = 12/3
    a = 4
    》-2a + b = -1
    -2 (4) + b = -1
    -8 + b = -1
    b = -1 + 8
    b = 7
    》5a + b
    5 (4) + 7
    20 + 7 = 27

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