Matematika

Pertanyaan

nilai lim x→π/4 1-sin 2x/cos² 2x

1 Jawaban

  • cos^2 2x = 1- sin^2 2x
    = (1-sin2x)(1+sin2x)

    lim"x->π/4" (1-sin2x)/(1-sin2x)(1+sin2x)
    = lim"x->π/4" 1/(1+sin2x)
    = 1/(1+sin π/2)
    = 1/2

Pertanyaan Lainnya