(64 pangkat min 4)1/6+(27)⅓-(125)⅔
Matematika
Cindym07
Pertanyaan
(64 pangkat min 4)1/6+(27)⅓-(125)⅔
1 Jawaban
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1. Jawaban Shafiranhar04
((64^-4)1/6)+(27^1/3)-(125^2/3)
= (64^-2/3)+((3^3)^1/3)-((5^3)^2/3)
= (4^3)^-2/3 + 3 - 5^2
=4^-2 +3 -25
= -16+3-25
=-13-25
=38
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