tolong 1 soal ini pake cara ya

AD // DC, AD // BC
a. <AEB = <DEC = 125
    <BAE = <ECD = 25
    <ABE = 180° - (125 + 25) = 30°
b. <CEB = (360° - (2x125)/2) = (360 - 250)/2 = 110/2 = 55
    <DAE = < ECB = 45
    <EBC = 180 - (45 + 55) = 180 - 100 = 80° 
c. <ACD = <ECD = <AEB = 25°
d. <ADB = <ADE = <EBC = 80°
e. <ACB = <DAE = < ECB = 45°
f. <ABC = <ABE + <EBC = 30+80 =110°