tentukan ph larutan nh4cl 0.1 mol (kb. nh 3 : 1,8 .10-5)

→ Kb NH3 = 1,8 x 10^-5

pKb = - log Kb
pKb = -log 1,8 x 10^-5
pKb = 5 - log 1,8
pKb = 5 - 0,25
pKb = 4,75

pH = 1/2 (14 - pKb - log10^-2)
pH = 1/2 (14 - 4,75 - 2)
pH = 1/2 (7,25)
pH = 3,625