F(x) = 1/2x-1 g(x) = 2x +4 .Fungsi(gof)-1 (10) adalah
Matematika
200601
Pertanyaan
F(x) = 1/2x-1 g(x) = 2x +4 .Fungsi(gof)-1 (10) adalah
1 Jawaban
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1. Jawaban 4LL
Langsung aja y
f{f`¹(x)} = x
1/2f`¹(x)-1 = x
2x.f`¹(x) - x = 1
f`¹(x) = 1+x / 2x
g{g`¹(x)} = x
2g`¹(x) + 4 = x
g`¹(x) = x-4 / 2
(gof)`¹(x) = f`¹og`¹(x)
= f`¹{g`¹(x)}
= 1+g`¹(x) / 2g`¹(x)
= (1+(x-4 / 2) : 2(x-4 / 2)
= (2+x-4)/2 : (x-4)
= (x-2)/2 × 1/(x-4)
= (x-2) / (2x-8)
(gof)`¹(10) = (10-2) / (2.10 - 8) = 8/12 = ⅔
Semoga berguna +_+