f(x)=x^2+1 dan g(x)=x+1, maka (fog)(x)-(gof)(x)=..... tolong langkah pengerjaannya juga

f(x) =x²+1 dan
g(x)=x+1,

¤nilai
(fog)(x)=(f(g(x)))
(fog)(x)=(f(g(x)))= (g(x))²+1=
(fog)(x)=(f(g(x)))= (x+1)²+1=
(fog)(x)=(f(g(x)))= (x²+2x+1)+1=
(fog)(x)=(f(g(x)))= x²+2x+1+1=
(fog)(x)=(f(g(x)))= x²+2x+2.

¤nilai
(gof)(x)=(g(f(x)))
(gof)(x)=(g(f(x)))= (f(x))+1
(gof)(x)=(g(f(x)))= (x²+1)+1
(gof)(x)=(g(f(x)))= x²+1+1
(gof)(x)=(g(f(x)))= x²+2

maka
[(fog)(x)] - (gof)(x)=
[x²+2x+2] - [x²+2]
x²+2x+2-x²-2 =
x²-x²+2x+2-2 = 2x

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