pada trapesium abcd dengan AB//CD, perbandingan besar sudut ADC dan sudut DAB 3 : 2 serta sudut BCD=5/3 sudut CBA. Tentukan besar sudut - sudut pada trapesium t

∠ADC/∠DAB = 3/2
∠ADC = 3/2. ∠DAB

∠ADC + ∠DAB = 180
3/2 ∠DAB + ∠DAB = 180
5/2 ∠DAB = 180
∠DAB = 180.2/5
∠DAB = 72°

∠ADC = 3/2. ∠DAB
∠ADC = 3/2.72
∠ADC = 108°

∠BCD = 5/3.∠CBA

∠BCD + ∠CBA = 180
5/3 ∠CBA + ∠CBA = 180
8/3 ∠CBA = 180
∠CBA = 180.3/8
∠CBA = 67,5°

∠BCD = 5/3.∠CBA
∠BCD = 5/3.67,5
∠BCD = 112,5°