Logaritma nomer 1 gimana ya?

m / n
= (²log a/³log b) / (³log a/²log b)
= (²log a/³log b) × (²log b/³log a)
= (²log a / ³log a) × (²log b /³log b)
= (²log a × ^alog 3) × (²log b × ^blog 3)
= ²log 3 × ²log 3
= (²log 3)²