Diketahui fungsi f(x)=2-x, g(x)=x²+1 dan h(x)=3x.Tentukan: a.(f o g o g)(x) b.(h o g o f)(x)

a) (fogoh)(x) = f(g(h(x))) = f(g(3x))
= f((3x)² + 1)
= f(9x² + 1)
= 2 - (9x² + 1)
= 2 - 9x² - 1
= 1 - 9x²