Matematika

Pertanyaan

Sistem persamaan linear 3 variabel:
2x + 3y - z = 20
3x + 2y + z = 20
x + 4y + 2z = 15

2 Jawaban

  • 2x + 3y - z = 20
    3x + 2y + z = 20
    ----------------------- +
    5x + 5y = 40

    3x + 2y + z = 20 || ×2
    x + 4y + 2z = 15 || ×1
    ------------------------------
    6x + 4y + 2z = 40
    x + 4y + 2z = 15
    --------------------------- -
    5x = 25
    x = 5

    5x + 5y = 40
    5(5) + 5y = 40
    25 + 5y = 40
    5y = 15
    y = 3

    2x + 3y - z = 20
    2(5) + 3(3) - z = 20
    10 + 9 - z = 20
    z = -1
  • 2x + 3y - z = 20 pers(1)
    3x + 2y + z = 20 pers(2)
    x + 4y + 2z = 15 pers(3)

    eliminasikan pers (1) dan (2)
    2x + 3y - z = 20
    3x + 2y + z = 20
    tambahkan
    5x + 5y = 40
    atau
    x + y = 8 pers(4)


    eliminasikan pers (2) dan (3)
    sebelumnya pers(3)
    x + 4y + 2z = 15 bagi 2 kedua ruas
    ½x + 2y + z = 15/2

    jadi
    ½x + 2y + z = 15/2
    3x + 2y + z = 20
    kurangkan
    -5/2x = (15/2 - 20)
    -5/2x = -25/2
    x = (-25/2) x (-2/5)
    x=-25/-5
    x=5

    x + y = 8
    y = 8-5
    y = 3

    2x + 3y -z =20
    2(5)+3(3)-z=20
    -z=20-19
    -z=1
    z=-1
    jadi nilai x y z ={ 5,3,-1}

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