Soal mat. Tolong bantu ya. Thank you

f(x) = ax^2 + bx + c mencapai minimum di (-2,1) = (xp,yp)
y = a(x - xp)^2 + yp
y = a(x - (-2))^2 + 1
y = a(x^2 + 4x + 4) + 1
f(x) = ax^2 + 4ax + 4a + 1
Karena minimum maka a > 0
a = 1 => f(x) = x^2 + 4x + 5
a = 2 => f(x) = 2x^2 + 8x + 9
a = 3 => f(x) = 3x^2 + 12x + 13
Dan seterusnya, jadi kita lihat bahwa
c > b > a > 0